{"id":13749,"date":"2019-05-03T15:27:32","date_gmt":"2019-05-03T20:27:32","guid":{"rendered":"http:\/\/circassiancenter.com\/tr\/?p=13749"},"modified":"2019-05-03T15:27:32","modified_gmt":"2019-05-03T20:27:32","slug":"fibonacci-sayi-dizisiyle-beste-yapsak-ortaya-ne-cikar-sizce","status":"publish","type":"post","link":"https:\/\/www.circassiancenter.com\/tr\/fibonacci-sayi-dizisiyle-beste-yapsak-ortaya-ne-cikar-sizce\/","title":{"rendered":"F\u0130BONACC\u0130\u00a0 SAYI\u00a0 D\u0130Z\u0130S\u0130YLE\u00a0 BESTE YAPSAK, ORTAYA NE \u00c7IKAR S\u0130ZCE?"},"content":{"rendered":"


\nM\u0131s\u0131r\u2019daki piramitler,\u00a0 Vinci\u2019nin Mona Lisa tablosu, ay \u00e7i\u00e7e\u011fi, salyangoz, y\u00fcz\u00fcm\u00fcz, parmaklar\u0131m\u0131z,\u00a0 \u00e7am\u00a0 kozala\u011f\u0131\u00a0 ve\u00a0 hatta t\u00fcm\u00a0 v\u00fccudumuz bu say\u0131 dizisine \/ alt\u0131n orana sahip. Daha basit anlat\u0131m\u0131yla alt\u0131n oran;\u00a0 b\u00fct\u00fcn\u00fcn,\u00a0 par\u00e7alar\u0131\u00a0 aras\u0131nda olan geometrik\u00a0 ve\u00a0 say\u0131sal oran ba\u011flant\u0131s\u0131d\u0131r.<\/span>
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233,\u00a0 377,\u00a0 610,\u00a0 987…\u00a0\u00a0 <\/span> Fibonacci say\u0131 dizisinin<\/span>\u00a0 \u00f6zelli\u011fi\u00a0 kendinden\u00a0 \u00f6nceki\u00a0 iki ard\u0131\u015f\u0131k\u00a0 <\/span>say\u0131n\u0131n<\/span>\u00a0 toplam\u0131n\u0131n\u00a0 kendisinden sonraki\u00a0 say\u0131ya\u00a0 e\u015fit\u00a0 olmas\u0131d\u0131r.\u00a0 Yani her <\/span> say\u0131<\/span> kendisinden \u00f6nce gelen iki <\/span>say\u0131n\u0131n<\/span> toplam\u0131d\u0131r. Buyurun size bir <\/span> <\/span>Tav\u015fan Problemi<\/strong>
\n\u201cD\u00f6rt yan\u0131 duvarlarla \u00e7evrili bir yere bir \u00e7ift tav\u015fan konmu\u015ftur. Her \u00e7ift tav\u015fan\u0131n bir ay i\u00e7inde yeni bir \u00e7ift tav\u015fan yavrulad\u0131\u011f\u0131, her yeni \u00e7iftin de erginle\u015fmesi i\u00e7in bir ay gerekti\u011fi ve tav\u015fanlar\u0131n \u00f6lmedi\u011fi varsay\u0131l\u0131rsa, 100 ay sonunda d\u00f6rt duvar\u0131n aras\u0131nda ka\u00e7 \u00e7ift tav\u015fan olur?\u201d Bu \u015fekilde d\u00fc\u015f\u00fcn\u00fcld\u00fc\u011f\u00fc takdirde tav\u015fan \u00e7iftleri aylara g\u00f6re \u015fu s\u0131ralamay\u0131 ortaya koymaktad\u0131r: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,\u2026
\nG\u00f6r\u00fcld\u00fc\u011f\u00fc gibi ilk iki say\u0131 hari\u00e7, her say\u0131 kendisinden \u00f6nce gelen iki say\u0131n\u0131n toplam\u0131na e\u015fittir. Bu say\u0131lar\u0131n aras\u0131ndaki oran ise bize alt\u0131n oran\u0131 vermektedir.<\/p>\n